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Three Big Ten Teams to Compete in Round of 16 at the NCAA Men's Tennis Championships
May 14, 2008
Complete Release in PDF Format
The field has been narrowed to 16 teams in the 2008 NCAA Men's Tennis Championships. Three Big Ten teams remain in No. 15 Illinois, No. 16 Michigan and No. 2 Ohio State with competition taking place May 16-20 in Tulsa, Okla. The Illini and Buckeyes will square off against one another on Friday, May 16 beginning at 3 p.m. CT. To earn its way to the round of 16, Illinois swept Xavier, 4-0, in the first round, and then defeated LSU, 4-2, in second-round competition. Ohio State swept both of its opponents, topping Cleveland State and East Tennessee State, 4-0, in each match. Illinois and OSU have met twice this season with the Buckeyes taking both matches. In Champaign on April 12, Ohio State won by a score of 5-2. The two schools met again for the Big Ten Championship with OSU narrowly defeating the Illini, 4-3. Michigan will battle top-seeded Virginia on Friday, May 16, at Noon CT. The Wolverines notched a first-round win over Western Michigan, 4-1, and was triumphant over Texas Tech, 4-2, in second-round play. The Cavaliers earned their way to the round of 16 with wins over Fairleigh Dickinson and Penn State in the opening weekend. In addition, the singles and doubles tournaments will take place after the conclusion of the team championship on May 21-26. Illinois' Ruben Gonzales and Ryan Rowe, Ohio State's Bryan Koniecko, Justin Kronauge and Steven Moneke and Wisconsin's Moritz Baumann will compete in the singles tournament. Four Big Ten duos will participate in the doubles tournament in Illinois' Billy Heiser and Rowe, Michigan State's Adam Monich and Nick Rinks and Ohio State has two teams in Koniecko and Moneke as well as Drew Eberly and Kronauge. Since 2000, the Big Ten has one national team title, one singles crown and three doubles championships. All of those earned by Illinois.
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